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Using given data, calculate the change in Gibbs free energy for each of the following reactions.

CH_{4}(g) + 4F_{2}(g) → CF_{4}(g) + 4HF(g)

Gibbs free energy for CH_{4}(g) is -50.8 kJ/mol

Gibbs free energy for CF_{4}(g) is -635.1 kJ/mol

Gibbs free energy for HF(g) is -270.70 kJ/mol

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