Ch. 17 - Chemical ThermodynamicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The oxidation of glucose (C6 H12 O6 ) in body tissue produces CO2 and H2 O. In contrast, anaerobic decomposition, which occurs during fermentation, produces ethanol (C2 H5 OH) and CO2.Using data given in Appendix C in the textbook, compare the equilibrium constants for the following reactions: (a) C6 H12 O6 (s) + 6O2 (g) ⇄ 6CO2 (g) + 6H2 O(l) (b) C6 H12 O6 (s) ⇄ 2C2 H5 OH(l) + 2CO2 (g)

Problem

The oxidation of glucose (C6 H12 O6 ) in body tissue produces CO2 and H2 O. In contrast, anaerobic decomposition, which occurs during fermentation, produces ethanol (C2 H5 OH) and CO2.

Using data given in Appendix C in the textbook, compare the equilibrium constants for the following reactions:
(a) C6 H12 O6 (s) + 6O2 (g) ⇄ 6CO2 (g) + 6H2 O(l)
(b) C6 H12 O6 (s) ⇄ 2C2 H5 OH(l) + 2CO2 (g)