Ch. 17 - Chemical ThermodynamicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The oxidation of glucose (C6 H12 O6 ) in body tissue produces CO2 and H2 O. In contrast, anaerobic decomposition, which occurs during fermentation, produces ethanol (C2 H5 OH) and CO2.Using data given

Problem

The oxidation of glucose (C6 H12 O6 ) in body tissue produces CO2 and H2 O. In contrast, anaerobic decomposition, which occurs during fermentation, produces ethanol (C2 H5 OH) and CO2.

Using data given in Appendix C in the textbook, compare the equilibrium constants for the following reactions:
(a) C6 H12 O6 (s) + 6O2 (g) ⇄ 6CO2 (g) + 6H2 O(l)
(b) C6 H12 O6 (s) ⇄ 2C2 H5 OH(l) + 2CO2 (g)