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The dissociation of AgIO3 in water is as follows:
AgIO3(s) ⇌ Ag+(aq) + IO3–(aq)
The molar mass of AgIO3 is:
AgIO3 1 Ag × 107.9 g/mol Ag = 107.90 g/mol
1 I × 126.9 g/mol I = 126.90 g/mol
3 O × 16.00 g/mol O = 48.00 g/mol
Total: 282.80 g/mol
Converting g/L to mol/L:
= 1.73 × 10–4 mol/L
If 0.0490 g of AgIO3 dissolves per liter of solution, calculate the solubility-product constant.
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