# Problem: A voltaic cell utilizes the following reaction:2Fe3+(aq) + H2(g)  →  2Fe2+(aq) + 2H+(aq).What is the emf of this cell under standard conditions?

###### FREE Expert Solution

Loss Electrons → Oxidation

Gain Electrons → Reduction2

Reduction:     2 Fe3+(aq) →  2 Fe2+(aq)

Oxidation:      H2(g)  → 2 H+(aq)

Fe3+(aq) + e →  Fe2+                          E° = 0.771 V
2 H+(aq) + 2 e H2(g)                        E°= 0.00 V

To calculate for the standard cell potential, use the following equation:

$\overline{){\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{cell}}}{\mathbf{=}}{\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{cathode}}}{\mathbf{-}}{\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{anode}}}}$

100% (296 ratings) ###### Problem Details
A voltaic cell utilizes the following reaction:
2Fe3+(aq) + H2(g)  →  2Fe2+(aq) + 2H+(aq).

What is the emf of this cell under standard conditions?

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