Loss Electrons → Oxidation
Gain Electrons → Reduction2
Reduction: 2 Fe3+(aq) → 2 Fe2+(aq)
Oxidation: H2(g) → 2 H+(aq)
Fe3+(aq) + e– → Fe2+ E° = 0.771 V
2 H+(aq) + 2 e– → H2(g) E°= 0.00 V
To calculate for the standard cell potential, use the following equation:
What is the emf of this cell under standard conditions?
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