Problem: The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook:l Ag+ (aq) + e-  →  Ag(s)Cu2 +  (aq) + 2e-  →  Cu(s)Ni2 +  (aq) + 2e-  →  Ni(s)Cr3 +  (aq) + 3e-  →  Cr(s).Determine which combination of these half-cell reactions leads to the cell reaction with the smallest positive cell emf.

FREE Expert Solution

We’re being asked to determine which combination of these half-cell reactions leads to the cell reaction with the smallest positive cell emf.


Recall that the standard cell potential, E°cell or emf is given by the equation:


E°cell=E°cathode-E°anode  


To do so, we need to do the following:  


Step 1. Determine the half-cell potentials (refer to the Standard Reduction Potential Table)
Step 2. Identify the oxidation half-reaction (anode) and the reduction half-reaction (cathode)
Step 3. Calculate E°cell for each combination of half-cell reactions


86% (330 ratings)
View Complete Written Solution
Problem Details
The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook:
l Ag+ (aq) + e-  →  Ag(s)
Cu2 +  (aq) + 2e-  →  Cu(s)
Ni2 +  (aq) + 2e-  →  Ni(s)
Cr3 +  (aq) + 3e-  →  Cr(s).



Determine which combination of these half-cell reactions leads to the cell reaction with the smallest positive cell emf.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Cell Potential concept. If you need more Cell Potential practice, you can also practice Cell Potential practice problems.