What is the maximum mass of aluminum chloride that could be obtained from 6.00 mol of barium chloride and excess aluminum sulfate? This is the balanced equation for the reaction?
Al2(SO4)3 + 3 BaCl2 → 3 BaSO4 + 2 AlCl3
a) 1250 g
b) 801 g
c) 534 g
d) 134 g
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