Problem: What is the maximum mass of aluminum chloride that could be obtained from 6.00 mol of barium chloride and excess aluminum sulfate? This is the balanced equation for the reaction?Al2(SO4)3 + 3 BaCl2 → 3 BaSO4 + 2 AlCl3a) 1250 gb) 801 gc) 534 gd) 134 g

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What is the maximum mass of aluminum chloride that could be obtained from 6.00 mol of barium chloride and excess aluminum sulfate? This is the balanced equation for the reaction?

Al2(SO4)3 + 3 BaCl2 → 3 BaSO4 + 2 AlCl3

a) 1250 g

b) 801 g

c) 534 g

d) 134 g

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