Problem: Consider the following reaction: PbCO3 (s) ⇌ PbO(s) + CO2 (g)Using data in Appendix C in the textbook, calculate the equilibrium pressure of CO2 in the system at 220 oC.

FREE Expert Solution

Step 1

H°rxn = H°product - H°reactantH°rxn =[1 mol PbO (- 217.3 kJ1 mol PbO) + 1 mol CO2(- 393.5 kJ1 mol CO2)]              - [1 mol PbCO3(- 699.1 kJ1 mol PbCO3)]H°rxn =88.3 kJ ×103 J1 kJ

ΔH°rxn = 88300 J


Step 2

S°rxn = S°product - S°reactantS°rxn =[1 mol PbO (68.7 J1 mol PbO·K) + 1 mol CO2(213.8 J1 mol CO2·K)]              - [1 mol PbCO3(131.0 J1 mol PbCO3·K)]

ΔS°rxn = 151.5 J/K


Step 3

T = 220°C + 273.15 = 493.15 K


G°rxn =H°rxn - TS°rxnG°rxn =88300 J -(493.15 K)(151 JK)G°rxn =88300 J - 74465.65 J

ΔG°rxn = 13834.35 J


View Complete Written Solution
Problem Details
Consider the following reaction: PbCO3 (s) ⇌ PbO(s) + CO2 (g)


Using data in Appendix C in the textbook, calculate the equilibrium pressure of CO2 in the system at 220 oC.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gibbs Free Energy concept. You can view video lessons to learn Gibbs Free Energy. Or if you need more Gibbs Free Energy practice, you can also practice Gibbs Free Energy practice problems.