• C2H5COONa will break up in the solution
▪ C2H5COO- → weak base (conjugate base)
[C2H5COO-] = [C2H5COONa]
▪ Na+ → neutral ion → will not contribute to pH
• C2H5COOH → weak acid
• The solution is composed of a weak acid and its conjugate base, therefore we have a buffer.
Step 1: Calculate the pKa of the weak acid.
Ka C2H5COOH = 1.34x10-5
pKa = 4.87
Step 2: Create an ICF chart and determine the final amounts of species present after the reaction.
▪ weak acid + conjugate base = buffer
Step 3: Calculate the pH of the solution.
A buffer contains 0.16 mol of propionic acid (C2H5COOH) and 0.22 mol of sodium propionate (C2H5COONa) in 1.20 L.
What is the pH of the buffer after the addition of 0.02 mol of NaOH?
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