Given: 0.085 M Pb2+ and 0.025 M Ag+ → addition of NaCl will precipitate chlorides (PbCl2 and AgCl)
Ksp of PbCl2 = 1.7 × 10–5
Ksp of AgCl = 1.8 × 10–10 → lower Ksp → precipitates first
A solution is 0.085 M in Pb2+ and 0.025 M in Ag+. If selective precipitation is to be achieved using NaCl, what minimum concentration of NaCl do you need to begin to precipitate the ion that precipitates first?
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