Problem: The molar solubility of AgBr in pure water is 7.3 x 10–7M. Calculate Ksp.

FREE Expert Solution
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FREE Expert Solution

Since the AgBr is an ionic compound, it forms ions when dissociating in water. The dissociation of AgBr in water is as follows:

AgBr(s)  Ag+(aq) + Br(aq)


The Ksp expression for AgBr is:

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Problem Details
The molar solubility of AgBr in pure water is 7.3 x 10–7M. Calculate Ksp.

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