Problem: Consider the evaporation of methanol at 25.0 ˚C: CH3OH(l)  →  CH3OH(g).The vapor pressure of methanol is 143 mmHg. Identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0oC and standard pressure (760 mmHg).

FREE Expert Solution

We're being asked to explain why methanol spontaneously evaporates in open air at 25.0°C and standard pressure (760 mmHg).

Note that the boiling point of a liquid is the temperature at which the vapor pressure of the liquid equals the external pressure on the liquid

View Complete Written Solution
Problem Details

Consider the evaporation of methanol at 25.0 ˚C: CH3OH(l)  →  CH3OH(g).

The vapor pressure of methanol is 143 mmHg. Identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0oC and standard pressure (760 mmHg).


Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gibbs Free Energy concept. You can view video lessons to learn Gibbs Free Energy. Or if you need more Gibbs Free Energy practice, you can also practice Gibbs Free Energy practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Craig's class at UW-SEATTLE.