We're being asked to explain why methanol spontaneously evaporates in open air at 25.0°C and standard pressure (760 mmHg).
Note that the boiling point of a liquid is the temperature at which the vapor pressure of the liquid equals the external pressure on the liquid.
Consider the evaporation of methanol at 25.0 ˚C: CH3OH(l) → CH3OH(g).
The vapor pressure of methanol is 143 mmHg. Identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0oC and standard pressure (760 mmHg).
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