Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: An electrochemical cell is based on the following two half-reactions:Ox: Pb(s) → Pb2+(aq, 0.21 M) + 2 e–Red: MnO4–(aq, 1.50 M) + 4 H+(aq, 2.1 M) + 3 e– → MnO2(s) + 2 H2O(l)Compute the cell potential a

Problem

An electrochemical cell is based on the following two half-reactions:
Ox: Pb(s) → Pb2+(aq, 0.21 M) + 2 e
Red: MnO4(aq, 1.50 M) + 4 H+(aq, 2.1 M) + 3 e → MnO2(s) + 2 H2O(l)
Compute the cell potential at 25 ˚C.