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Solution: A 0.229-g sample of an unknown monoprotic acid was titrated with 0.112 M NaOH and the resulting titration curve is shown  in the figure.Determine the molar mass of the acid.

Problem

A 0.229-g sample of an unknown monoprotic acid was titrated with 0.112 M NaOH and the resulting titration curve is shown  in the figure.

Determine the molar mass of the acid.

A graph of pH versus Volume of base added (mL). At 0 mL of base the pH starts out at about 2 then steadily increases as base is added. At about 25 mL of base added the graph is almost vertical from a pH of about 5 to 11. As more base is added past 25 mL the pH goes back to a steady increase up to 60 mL where the pH is about 13.

Solution

We’re being asked to calculate the molar mass of an unknown acid based on our interpretation of the titration curve


Recall that at the equivalence point of a titration:


moles acid=moles base


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