Problem: A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 M HCl.Calculate the pH at 20 mL of added acid.

FREE Expert Solution

We’re being asked to calculate the pH of a solution after the addition of 20.0 mL 0.100 M HCl solution. The solution is made up of 25.00 mL of 0.125 M pyridine (C5H5N).


HCl (strong acid) will react with C5H5N (base).

▪ C5H5N is a weak base and based on Bronsted-Lowry definition it is a proton acceptor.
▪ HCl is a strong acid and based on Bronsted-Lowry definition it is a proton donor.

Reaction:

C5H5N(aq) + HCl(aq)C5H5NH+(aq) + Cl-(aq)


We will calculate the pH of the solution using the following steps:

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Problem Details

A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 M HCl.

Calculate the pH at 20 mL of added acid.