Problem: If a solution of HF (Ka = 6.8x10–4) has a pH of 3.10, calculate the concentration of hydrofluoric acid.

FREE Expert Solution

HF H+ + F


Step 1

[H+] = 10-pH[H+] =10-3.10

[H+] = 7.943x10-4 M


Step 2

Ka =[H+][F-][HF][H+] = [F-]Ka = [H+]2[HF][HF] = [H+]2Ka[HF] = 7.943×10-326.8×10-4


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Problem Details

If a solution of HF (Ka = 6.8x10–4) has a pH of 3.10, calculate the concentration of hydrofluoric acid.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Weak Acids concept. If you need more Weak Acids practice, you can also practice Weak Acids practice problems.

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