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🤓 Based on our data, we think this question is relevant for Professor Du's class at UGA.
HF ⇌ H+ + F‑
[H+] = 10-pH[H+] =10-3.10
[H+] = 7.943x10-4 M
Ka =[H+][F-][HF][H+] = [F-]Ka = [H+]2[HF][HF] = [H+]2Ka[HF] = 7.943×10-326.8×10-4
If a solution of HF (Ka = 6.8x10–4) has a pH of 3.10, calculate the concentration of hydrofluoric acid.
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