We’re being asked to calculate the equilibrium concentration of chloroacetic acid (ClCH2COOH) if the percent dissociation of 0.100 M ClCH2COOH is 11.0%.
Recall that the percent dissociation is given by:
Remember that weak acids partially dissociate in water and that acids donate H+ to the base (water in this case).
The dissociation of ClCH2COOH is as follows:
ClCH2COOH(aq) + H2O(l) ⇌ H3O+(aq) + ClCH2COO–(aq)
A 0.100 M solution of chloroacetic acid (ClCH2 COOH) is 11.0% ionized.
Using this information, calculate [ClCH2 COOH] for chloroacetic acid.
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