We’re being asked to calculate the energy released for the following nuclear reaction:

${}_{\mathbf{10}}{}^{\mathbf{21}}\mathit{N}\mathit{e}\mathbf{+}{}_{\mathbf{2}}{}^{\mathbf{4}}\mathit{H}\mathit{e}\mathbf{\to}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathit{n}\mathbf{+}{}_{\mathbf{12}}{}^{\mathbf{24}}\mathit{M}\mathit{g}$

To calculate the energy released for the reaction, we’re going to use the following steps:

*Step 1**: Calculate the mass defect (Δm).***Step 2**: Calculate the mass defect (Δm) in kg.**Step 3**: Calculate the energy released (E).

**Step 1: Calculate the mass defect (Δm).**

**Given:**

How much energy is released in the following nuclear reaction?

Mass of the ^{21}Ne = 20.993849 amu; Mass of ^{4}He = 4.002604 amu;

Mass of a neutron = 1.008665; Mass of ^{24}Mg = 23.985045

(a) 9.51 x 10^{7} kJ.mol

(b) 471 kJ.mol

(c) 9.22 x 10^{10} kJ/mol

(d) 7.65 x 10^{4} kJ/mol

(e) 2.47 x 10^{8} kJ/mol

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Based on our data, we think this problem is relevant for Professor Naleway's class at LUC.