Problem: Find the pH and percent ionization of each HF solution. (Ka for HF is 6.8 x 10-4.)Find the percent dissociation of a 0.270 M HF solution.

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FREE Expert Solution

Recall that the percent ionization is given by:


% ionization=[H+][HA]initial×100



The dissociation of HA is as follows:

HF(aq) + H2O(l) ⇌ H3O+(aq) + F–(aq); Ka = 6.8 × 10–4


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Problem Details

Find the pH and percent ionization of each HF solution. (Ka for HF is 6.8 x 10-4.)

Find the percent dissociation of a 0.270 M HF solution.

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