We are asked to calculate the amount of NaCN in a mixture of NaCN and NaHSO4 consisting of a total of 0.60 mol. When the mixture is dissolved in 1.0 L of water and comes to equilibrium the pH is found to be 9.6.
NaCN and NaHSO4 are both ionic compounds of sodium with conjugate bases of weak acid CN- and strong acid HSO4-
The dissociation of NaCN and NaHSO4 are as follows:
NaCN (aq) → Na+ (aq) + CN- (aq)
NaHSO4(aq) → Na+(aq) + HSO4-(aq)
A mixture of NaCN and NaHSO4 consists of a total of 0.60 mol. When the mixture is dissolved in 1.0 L of water and comes to equilibrium the pH is found to be 9.6.
Find the amount of NaCN in the mixture.
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