Problem: Consider a 0.10 M solution of a weak polyprotic acid (H2 A) with the possible values of Ka1  and Ka2  given below. Calculate the contributions to [H3O+] from each ionization step.Ka1  = 1.0x10 - 4 ; Ka2  = 5.0x10 - 5

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 We are being asked to calculate the contributions to [H3O+] from each ionization step in H2A.

H2A

can donate two protons (H+) → diprotic acid
two equilibrium equations → two equilibrium constants
Equilibrium constants (Ka) given:

Ka1 = 1.0x10-4

Ka2 = 5.0x10-5


Construct an ICE Chart for the 1st equilibrium reaction:

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Problem Details

Consider a 0.10 M solution of a weak polyprotic acid (H2 A) with the possible values of Ka1  and Ka2  given below. Calculate the contributions to [H3O+] from each ionization step.

Ka1  = 1.0x10 - 4 ; Ka2  = 5.0x10 - 5

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Our tutors have indicated that to solve this problem you will need to apply the Diprotic Acid concept. You can view video lessons to learn Diprotic Acid. Or if you need more Diprotic Acid practice, you can also practice Diprotic Acid practice problems.