Solution: Diatomic iodine (I2) decomposes at high temperature to form I atoms according to the reaction: I2(g) ⇌ 2I(g), Kc = 0.011 at 1200 oCIn an equilibrium mixture, the concentration of I2 is 0.18 M. What is

Diatomic iodine (I₂) decomposes at high temperature to form I atoms according to the reaction: I₂(g) ⇌ 2I(g), K_c = 0.011 at 1200 ^oC

In an equilibrium mixture, the concentration of I₂ is 0.18 M. What is the equilibrium concentration of I?