# Problem: Consider the following reaction: H2(g) + I2(g) ⇌ 2HI(g)Complete the following table. Assume that all concentrations are equilibrium concentrations in M.T(oC)  [H2] (M)   [I2] (M) [HI] (M)    Kc25  0.0355  0.0388 0.922   –340- 4.60×10−2  0.390 90.6 445 4.90×10−2  4.72×10−2     – 50.2Find [HI] at 445 oC.

###### FREE Expert Solution

Recall that the equilibrium constant is the ratio of the products and reactants

H2(g) + I2(g) ⇌ 2HI(g)

The Kc expression for the reaction is:

$\overline{){{\mathbf{K}}}_{{\mathbf{c}}}{\mathbf{=}}\frac{\mathbf{\left[}\mathbf{products}\mathbf{\right]}}{\mathbf{\left[}\mathbf{reactants}\mathbf{\right]}}{\mathbf{=}}\frac{{\mathbf{\left[}\mathbf{HI}\mathbf{\right]}}^{\mathbf{2}}}{\mathbf{\left[}{\mathbf{H}}_{\mathbf{2}}\mathbf{\right]}\mathbf{\left[}{\mathbf{I}}_{\mathbf{2}}\mathbf{\right]}}}$

We’re given the following at 445 oC:

[H2] = 4.90 × 10−2 M              [HI] = ?

[I2] = 4.72 × 10−2 M                Kc = 50.2

86% (109 ratings) ###### Problem Details

Consider the following reaction: H2(g) + I2(g) ⇌ 2HI(g)
Complete the following table. Assume that all concentrations are equilibrium concentrations in M.

 T(oC) [H2] (M) [I2] (M) [HI] (M) Kc 25 0.0355 0.0388 0.922 – 340 - 4.60×10−2 0.390 90.6 445 4.90×10−2 4.72×10−2 – 50.2

Find [HI] at 445 oC.