Problem: When N2O5(g) is heated it dissociates into N2O3(g) and O2(g) according to the following reaction:N2O5(g) ⇌ N2O3(g) + O2(g); Kc = 7.75 at a given temperatureThe N2O3(g) dissociates to give N2O(g) and O2(g) according the following reaction:N2O3(g) ⇌ N2O(g) + O2(g); Kc = 4.00 at the same temperatureWhen 4.00 mol of N2O5(g) is heated in a 1.00-L reaction vessel to this temperature, the concentration of O2(g) at equilibrium is 4.50 mol/L. Find the concentration of N2O3 in the equilibrium system.

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FREE Expert Solution

Molarity(M)=molL


N2O5(g) ⇌ N2O3(g) + O2(g);          Kc = 7.75

[N2O5]=4.00 mol1.00 L

[N2O5] = 4.00 M

Kc=productsreactantsKc=[N2O3][O2][N2O5]7.75=(x)(4.5)(4.00-x)7.75(4.00-x)=4.5x31-7.75x=4.5x31=7.75x+4.5x3112.25=12.25x12.25

x = 2.5306

x = [N2O3]

[N2O3] = 2.5306 M



N2O3(g) ⇌ N2O(g) + O2(g);          Kc = 4.00

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Problem Details

When N2O5(g) is heated it dissociates into N2O3(g) and O2(g) according to the following reaction:

N2O5(g) ⇌ N2O3(g) + O2(g); Kc = 7.75 at a given temperature

The N2O3(g) dissociates to give N2O(g) and O2(g) according the following reaction:

N2O3(g) ⇌ N2O(g) + O2(g); Kc = 4.00 at the same temperature

When 4.00 mol of N2O5(g) is heated in a 1.00-L reaction vessel to this temperature, the concentration of O2(g) at equilibrium is 4.50 mol/L. Find the concentration of N2O3 in the equilibrium system.