Problem: Carbon monoxide and chlorine gas react to form phosgene: CO(g) + Cl2(g) ⇌ COCl2(g); Kp = 3.10 at 700 KIf a reaction mixture initially contains 326 torr of CO and 326 torr of Cl2, what is the mole fraction of COCl2 when equilibrium is reached?

🤓 Based on our data, we think this question is relevant for Professor Billman's class at Abilene Christian University.

FREE Expert Solution

Step 1

326 torr ×1 atm760 torr = 0.4289 atm


Step 2


Step 3

Kp = [COCl2][CO][Cl2]3.10 =x(0.4289-x)23.10 =x0.184 - 0.8578x + x23.10(0.184 - 0.8578 x + x2) = x0.5704 - 2.6592 x + 3.10 x2 = x0.5704 - 2.6592 x - x + 3.10 x2 =00.5704 - 3.6592 x + 3.10 x2 = 0


x = -b ± b2 - 4ac2ax =-(-3.6592) ± (-3.6592)2 - 4(0.5704)(3.10)2(3.10)x = 3.6592 ± 13.3897 - 7.07306.2x = 3.6592 ±6.31676.2x = 3.6592 ± 2.51336.2x = 3.6592 + 2.51336.2                       x = 3.6592 - 2.51336.2x = 6.17256.2                                          x = 1.14596.2x = 0.9956                                            x = 0.1848


concentration cannot be negative so we will use

x = 0.1848 atm


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Problem Details

Carbon monoxide and chlorine gas react to form phosgene: CO(g) + Cl2(g) ⇌ COCl2(g); Kp = 3.10 at 700 K

If a reaction mixture initially contains 326 torr of CO and 326 torr of Cl2, what is the mole fraction of COCl2 when equilibrium is reached?

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Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.