Problem: At 650 K, the reaction MgCO3(s) ⇌ MgO(s) + CO2(g) has Kp = 0.026. A 12.6 L container at 650 K has 1.0 g of MgO(s) and CO2 at P = 0.0260 atm. The container is then compressed to a volume of 0.600 L. Find the mass of MgCO3 that is formed.  

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FREE Expert Solution

Given reaction: MgCO3(s) ⇌ MgO(s) + CO2(g


Solve moles CO2:


PV=nRTn=PVRTn=0.0260 atm(12.6 L)(0.08206L·atmmol·K)(650 K)

nCO2 = 6.14 x 10-3 mol CO2


Solve moles MgO:


1.0  g MgO×1 mol MgO40.3 g MgO= 0.0248 mol MgO


ICE Chart(reverse reaction during compression)

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Problem Details

At 650 K, the reaction MgCO3(s) ⇌ MgO(s) + CO2(g) has Kp = 0.026. A 12.6 L container at 650 K has 1.0 g of MgO(s) and CO2 at P = 0.0260 atm. The container is then compressed to a volume of 0.600 L. Find the mass of MgCO3 that is formed.  

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Based on our data, we think this problem is relevant for Professor Broering's class at CU.