🤓 Based on our data, we think this question is relevant for Professor Broering's class at CU.
Given reaction: MgCO3(s) ⇌ MgO(s) + CO2(g
Solve moles CO2:
nCO2 = 6.14 x 10-3 mol CO2
Solve moles MgO:
0.0248 mol MgO
ICE Chart: (reverse reaction during compression)
At 650 K, the reaction MgCO3(s) ⇌ MgO(s) + CO2(g) has Kp = 0.026. A 12.6 L container at 650 K has 1.0 g of MgO(s) and CO2 at P = 0.0260 atm. The container is then compressed to a volume of 0.600 L. Find the mass of MgCO3 that is formed.
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Based on our data, we think this problem is relevant for Professor Broering's class at CU.