Problem: The mass of the atom  2311 Na is 22.9898 amu.(a) Calculate its binding energy per atom in millions of electron volts.

FREE Expert Solution

Step 1: Calculate the mass defect (Δm).

Given:

2311 Na is 22.9898 amu

mass 23Na = 22.9898 amu
mass neutron = 1.008665 amu
mass of proton
= 1.007277 amu


m=(mass Na1123)-[12(mass neutron)+11(mass proton)]m=(22.9898 amu)-[121.008665 amu+11(1.007277 amu)]             m=22.9898 amu-23.184027 amu

Δm = – 0.194227 amu


Step 2: Calculate the binding energy per atom in millions of electron volts.

View Complete Written Solution
Problem Details

The mass of the atom  2311 Na is 22.9898 amu.

(a) Calculate its binding energy per atom in millions of electron volts.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.