Problem: The experimentally determined rate law for the reaction 2 NO(g) + 2 H2(g) → N2(g) + 2 H2O(g) is Rate = k[NO]2[H2].If the concentration of H2 is doubled, will the reaction rate quadruple, double, or remain the same?

FREE Expert Solution

Recall that the rate law only focuses on the reactant concentrations and has a general form of:

rate law=kAxBy

k = rate constant
A & B = reactants
x & y = reactant orders


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Problem Details

The experimentally determined rate law for the reaction 2 NO(g) + 2 H2(g) → N2(g) + 2 H2O(g) is Rate = k[NO]2[H2].

If the concentration of H2 is doubled, will the reaction rate quadruple, double, or remain the same?

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