Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Arrange the following substances in order of increasing boiling point (highest boiling point LAST):  CH3CH2OH, HOCH2CH2OH, CH3CH2Cl, and ClCH2CH2OH   a) CH3CH2OH < CH3CH2Cl < HOCH2CH2OH <

Problem

Arrange the following substances in order of increasing boiling point (highest boiling point LAST): 

CH3CH2OH, HOCH2CH2OH, CH3CH2Cl, and ClCH2CH2OH

 

a) CH3CH2OH < CH3CH2Cl < HOCH2CH2OH < ClCH2CH2OH

b) CH3CH2OH < ClCH2CH2OH < CH3CH2Cl < HOCH2CH2OH

c) CH3CH2OH < HOCH2CH2OH < CH3CH2Cl < ClCH2CH2OH

d) CH3CH2Cl < CH3CH2OH < ClCH2CH2OH < HOCH2CH2OH

e) CH3CH2Cl < ClCH2CH2OH < CH3CH2OH < HOCH2CH2OH