Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The gas-phase reaction Cl(g) + HBr(g)HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ.What is the activation energy for the reverse reaction?

Problem

The gas-phase reaction Cl(g) + HBr(g)HCl(g) + Br(g) has an overall energy change of -66 kJ. The activation energy for the reaction is 7 kJ.

What is the activation energy for the reverse reaction?

Solution

We’re being asked to determine the activation energy for the reverse reaction when overall energy change of -66 kJ with activation energy is 7 kJ


We’re given the following information:


ΔH = –66 kJ: Recall that the change in enthalpy or overall energy change (ΔH) is the difference in energy between products and reactants. ΔH for the reaction is negative, which means we have an exothermic reaction. This signifies that the reactants are higher in energy than the products.


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