Problem: The mechanism for the oxidation of HBr by O2 to form 2 H2 O and Br2 is shown below.4HBr(g)+O2(g)2H2O(g)+2Br2(g)HBr(g)+O2(g)HOOBr(g) HOOBr(g)+HBr(g)2HOBr(g)HOBr(g)+HBr(g)H2O(g)+Br2(g).HBr does not react with O2 at a measurable rate at room temperature under ordinary conditions. What can you infer from this about the magnitude of the activation energy for the rate-determining step?

FREE Expert Solution

We're asked to state what we can infer about the magnitude of the activation energy for the rate-determining step based on the given mechanism for the oxidation of HBr by O2 to form 2 H2O and Br2


We also know that HBr does not react with O2 at a measurable rate at room temperature under ordinary conditions. 


Recall that the higher the activation energy, the slower the rate of a reaction


The overall reaction mechanism is: 4HBr(g)+O2(g)  2H2O(g)+2Br2(g)


The individual steps are:


(1) HBr(g)+O2(g)HOOBr(g) 

(2) HOOBr(g)+HBr(g)2HOBr(g)

(3) HOBr(g)+HBr(g)H2O(g)+Br2(g)


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Problem Details

The mechanism for the oxidation of HBr by O2 to form 2 H2 O and Bris shown below.


4HBr(g)+O2(g)2H2O(g)+2Br2(g)


HBr(g)+O2(g)HOOBr(g) 
HOOBr(g)+HBr(g)2HOBr(g)
HOBr(g)+HBr(g)H2O(g)+Br2(g).

HBr does not react with O2 at a measurable rate at room temperature under ordinary conditions. What can you infer from this about the magnitude of the activation energy for the rate-determining step?

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