Problem: In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:Step 1: (CH3)3AuPH3 ⇌ (CH3)3Au + PH3 (fast, k1: forward; k–1: reverse)Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow, k2)Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast, k3)What would be the effect on the reaction rate of adding PH3 to the solution of (CH3)3AuPH3?

FREE Expert Solution

When a reaction mechanism is given, the rate law can be determined using the slow step in the reaction mechanism.

 rate law only involves the reactants
▪ the coefficients of the reactants in the slow step are the order of the reaction with respect to that reactant
▪ Rate Law has a general form of:


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Problem Details

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:
Step 1: (CH3)3AuPH3 ⇌ (CH3)3Au + PH3 (fast, k1: forward; k–1: reverse)
Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow, k2)
Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast, k3)

What would be the effect on the reaction rate of adding PH3 to the solution of (CH3)3AuPH3?

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