Chemistry Practice Problems Integrated Rate Law Practice Problems Solution: The first-order rate constant for the decompositio...

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# Solution: The first-order rate constant for the decomposition of N2O5,2N2O5(g) → 4NO2(g) + O2(g)at 70oC is 6.82 x 10 - 3 s - 1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.1 L .How many moles of N2O5 will remain after 6.0 min ?

###### Problem

The first-order rate constant for the decomposition of N2O5,

2N2O5(g) → 4NO2(g) + O2(g)

at 70oC is 6.82 x 10 - 3 s - 1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.1 L .

How many moles of N2O5 will remain after 6.0 min ?

Integrated Rate Law

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#### Q. Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1 .What is the half-life for this reaction...

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Integrated Rate Law

#### Q. Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s-1 .If you start with 0.055 M of I2 at this...

Solved • Thu Dec 06 2018 09:35:34 GMT-0500 (EST)

Integrated Rate Law

#### Q. The first-order rate constant for the decomposition of N2O5,2N2O5(g) → 4NO2(g) + O2(g)at 70oC is 6.82 x 10 - 3 s - 1. Suppose we start with 2.60×10−2 ...

Solved • Thu Dec 06 2018 09:35:34 GMT-0500 (EST)