Problem: After four half-life periods for a first-order reaction, what fraction of reactant remains?

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We’re being asked to calculate the fraction of the reactant remaining after 4 half-lives


Recall that half-life is the time needed for the amount of a reactant to decrease by 50% or one-half. One way to determine the amount remaining after x half-lives is:


The half-life of a first order reaction is given by:

 t1/2=ln2k


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Problem Details

Time equals 0 minutes: 16 O, 0 N. Time equals 30 minutes: 4 O and 12 N.

After four half-life periods for a first-order reaction, what fraction of reactant remains?

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