Based on the graph:

y = ln [SO_{2}Cl_{2}]

x = time

The equation of the line is in the form of y = mx + b.

y = –0.000290t – 2.30

ln [SO_{2}Cl_{2}] = –0.000290t – 2.30

We can now predict the concentration of SO_{2}Cl_{2} at 1800 s.

t = 1800 s

Consider the equation for the decomposition of SO_{2}Cl_{2}: SO_{2}Cl_{2}(g) → SO_{2}(g) + Cl_{2}(g)

The graph of ln [SO_{2}Cl_{2}] versus time is

Use the graph and the best fitting line to predict the concentration of SO_{2}Cl_{2} at 1800 s.

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