Problem: The desorption (leaving of the surface) of a single molecular layer of n-butane from a single crystal of aluminum oxide was found to be first order with a rate constant of 0.128/s at 150 K.If the surface is initially completely covered with n-butane at 150 K, how long will it take for 25% of the molecules to desorb (leave the surface)?

🤓 Based on our data, we think this question is relevant for Professor Richert's class at ASU.

FREE Expert Solution

We’re being asked to determine the time it would take for 25% of the molecules to desorb (leave the surface)

The integrated rate law for a first order reaction is as follows:


ln At = -kt + ln Ao


where:

[A]t = concentration at time t, 

[A]0 = initial

k = rate constant, 

t = time


Since no concentration is given, we can use the given percentages in place of concentration.

View Complete Written Solution
Problem Details

The desorption (leaving of the surface) of a single molecular layer of n-butane from a single crystal of aluminum oxide was found to be first order with a rate constant of 0.128/s at 150 K.

If the surface is initially completely covered with n-butane at 150 K, how long will it take for 25% of the molecules to desorb (leave the surface)?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Integrated Rate Law concept. You can view video lessons to learn Integrated Rate Law. Or if you need more Integrated Rate Law practice, you can also practice Integrated Rate Law practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Richert's class at ASU.