Problem: The proposed mechanism for the formation of hydrogen bromide can be written in a simplified form as:Br2(g)  ⇌ 2 Br(g)          Fast, k1 (forward), k–1 (reverse)Br(g) + H2(g) → HBr(g) + H(g)          Slow, k2H(g) + Br2(g) → HBr(g) +  Br(g)          Slow, k3What rate law corresponds to this mechanism?

🤓 Based on our data, we think this question is relevant for Professor Dixon's class at UCF.

FREE Expert Solution

When a reaction mechanism is given, the rate law can be determined using the slow step in the reaction mechanism.

 rate law only involves the reactants
▪ the coefficients of the reactants in the slow step are the order of the reaction with respect to that reactant
▪ Rate Law has a general form of:

View Complete Written Solution
Problem Details

The proposed mechanism for the formation of hydrogen bromide can be written in a simplified form as:
Br2(g)  ⇌ 2 Br(g)          Fast, k1 (forward), k–1 (reverse)
Br(g) + H2(g) → HBr(g) + H(g)          Slow, k2
H(g) + Br2(g) → HBr(g) +  Br(g)          Slow, k3

What rate law corresponds to this mechanism?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Reaction Mechanism concept. If you need more Reaction Mechanism practice, you can also practice Reaction Mechanism practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Dixon's class at UCF.