We’re being asked to calculate the rate of the reaction be at [N2O5] = 0.055 M if the reaction were second order. We can calculate the rate constant of the reaction from its rate law.
Recall that the rate law only focuses on the reactant concentrations and has a general form of:
k = rate constant
A & B = reactants
x & y = reactant orders
Reaction: N2O5(g) → NO3(g) + NO2(g)
Given: Order with respect to N2O5(g) = 2
Rate constant =0.053 M/s
To determine the unit of k, we will use the following equation:
The following reaction is first order in N2O5: N2O5(g) → NO3(g) + NO2(g). The rate constant for the reaction at a certain temperature is 0.053/s. What would the rate of the reaction be at [N2O5] = 0.055 M if the reaction were second order? (Assume the same numerical value for the rate constant with the appropriate units.)
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