Problem: The easiest fusion reaction to initiate is21H + 31H → 42He + 10nCalculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.

FREE Expert Solution
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FREE Expert Solution

To calculate the energy released:

21H + 31H → 42He + 10n

Step 1: mass defect (Δm)

$\overline{){\mathbf{∆}}{\mathbf{m}}{\mathbf{=}}{\mathbf{p}}{\mathbf{r}}{\mathbf{o}}{\mathbf{d}}{\mathbf{u}}{\mathbf{c}}{\mathbf{t}}{\mathbf{s}}{\mathbf{-}}{\mathbf{r}}{\mathbf{e}}{\mathbf{a}}{\mathbf{c}}{\mathbf{t}}{\mathbf{a}}{\mathbf{n}}{\mathbf{t}}{\mathbf{s}}}$

Δm = – 0.01889 u or amu

Convert to kg: 1 amu = 1.6606x10-27 kg

Δm = – 3.1369 x10-29 kg

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Problem Details

The easiest fusion reaction to initiate is

21H + 31H → 42He + 10n

Calculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems .

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Based on our data, we think this problem is relevant for Professor Walker's class at TEXAS.

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