Problem: The easiest fusion reaction to initiate is21H + 31H → 42He + 10nCalculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.

FREE Expert Solution

To calculate the energy released:


21H + 31H → 42He + 10n


Step 1: mass defect (Δm)


m=products-reactants

m=mass He24+mass n01-mass H12+mass H13m=4.00260+1.00866 u             -2.01410 u+3.01605 um=5.01126 u-5.03015 amu

Δm = – 0.01889 u or amu


Convert to kg: 1 amu = 1.6606x10-27 kg

m=-0.01889 amu×1.6606×10-27 kg1 amu  

  Δm = – 3.1369 x10-29 kg

View Complete Written Solution
Problem Details

The easiest fusion reaction to initiate is

21H + 31H → 42He + 10n

Calculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.