# Problem: The most stable nucleus in terms of binding energy per nucleon is  56Fe. If the atomic mass of 56Fe is 55.9349 u, calculate the binding energy per nucleon for  56Fe.

###### FREE Expert Solution

Step 1: Calculate the mass defect (Δm).

Given:

mass 56Fe = 55.9349 u

atomic # Ti = # of protons = 26

mass # = 56

# of neutrons = 56 - 26 = 30

mass of proton = 1.007276 amu
mass neutron = 1.008665 amu

$\mathbf{∆}\mathbf{m}\mathbf{=}\mathbf{\left(}\mathbf{neutrons}\mathbf{+}\mathbf{protons}\mathbf{\right)}\mathbf{-}\mathbf{Fe}$

Δm = 0.514226 amu

Step 2: Calculate the mass defect (Δm) in kg.

1 amu = 1.6606x10-27 kg

Δm = 8.5392x10-28 kg

Step 3: Calculate the energy released (E).

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###### Problem Details

The most stable nucleus in terms of binding energy per nucleon is  56Fe. If the atomic mass of 56Fe is 55.9349 u, calculate the binding energy per nucleon for  56Fe.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.

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Based on our data, we think this problem is relevant for Professor Sharma's class at UM.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.