${\mathbf{N}}_{\mathbf{o}}\mathbf{=}\mathbf{28}\mathbf{}\overline{)\mathbf{mg}}\mathbf{\left(}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{g}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mg}}}\mathbf{\right)}\mathbf{\left(}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}\mathbf{}\mathbf{Cu}}}{\mathbf{64}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{Cu}}}\mathbf{\right)}\left(\frac{6.022\times {10}^{23}\mathrm{Cu}\mathrm{atoms}}{1\overline{)\mathrm{mol}\mathrm{Cu}}}\right)\mathbf{=}$**2.635×10**^{20}

Radioactive copper-64 decays with a half-life of 12.8 days.

b. A sample contains 28.0 mg ^{64}Cu. How many decay events will be produced in the first second? Assume the atomic mass of ^{64}Cu is 64.0 u.

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