Na2SO4 dissociates as Na+ and SO42-
Na+ → gains electrons → reduction → cathode
SO42- → loses electrons → oxidation → anode
Possible cathode reactions:
2 H2O (l) + 2e- → H2 (g) + 2OH- (aq) E = -0.83 V
Na+ (aq) + e- → Na (s) E = -2.71 V
In the electrolysis of an aqueous solution of Na2SO4, what reactions occur at the anode and the cathode (assuming standard conditions)?
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