Problem: An electrochemical cell consists of a silver metal electrode immersed in a solution with [Ag +] = 1.0 M separated by a porous disk from a copper metal electrode. If the copper electrode is placed in a solution of 5.0 M NH3 that is also 0.010 M in Cu(NH 3)4 2+, what is the cell potential at 25°C?Cu2+(aq) + 4NH3 (aq) ⇌ Cu(NH 3)4 2+(aq)          K = 1.0 X 10 13

FREE Expert Solution

Step 1

K = [CuNH34+][Cu2+][NH3]4[Cu2+] = [CuNH34+]K [NH3]4[Cu2+] =0.010(1.0×1013)(5.0)4

[Cu2+] = 1.6x10-18 M


Step 2


Cu2+ (aq) + 2 e- Cu (s)       E° = 0.34 V           E oxidation anode

Ag+ (aq) + e- Ag (s)            E° = 0.80 V           E reduction cathode


Step 3

E°cell = E°cathode - E°anodeE°cell =0.80 V - 0.34 V

cell = 0.46 V


Step 4


Cu (s) Cu2+ (aq) + 2 e-

[Ag+ (aq) + e- Ag (s)] x2


2 Ag+ (aq)  + Cu (s) Cu2+ (aq) + 2 Ag (s)


n = 2


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Problem Details

An electrochemical cell consists of a silver metal electrode immersed in a solution with [Ag +] = 1.0 M separated by a porous disk from a copper metal electrode. If the copper electrode is placed in a solution of 5.0 M NH3 that is also 0.010 M in Cu(NH 3)4 2+, what is the cell potential at 25°C?

Cu2+(aq) + 4NH3 (aq) ⇌ Cu(NH 3)4 2+(aq)          K = 1.0 X 10 13

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