Problem: The amount of manganese in steel is determined by changing it to permanganate ion. The steel is first dissolved in nitric acid, producing Mn2+ ions. These ions are then oxidized to the deeply colored MnO4- ions by periodate ion (IO4-) in acid solution.b. Calculate E° and ΔG° at 25°C for each reaction.

FREE Expert Solution

Write the half cell reactions:

IO4-  + 2 H+ 2 e→   IO3-  +  H2O                    E° = 1.60 V (reduction → cathode)

MnO4+ 8 H+  + 5e- →  Mn2+  + 4 H2          E° = 1.51 V (oxidation → anode)


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Problem Details

The amount of manganese in steel is determined by changing it to permanganate ion. The steel is first dissolved in nitric acid, producing Mn2+ ions. These ions are then oxidized to the deeply colored MnO4- ions by periodate ion (IO4-) in acid solution.

b. Calculate E° and ΔG° at 25°C for each reaction.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.