Write the half cell reactions:
IO4- + 2 H+ + 2 e- → IO3- + H2O E° = 1.60 V (reduction → cathode)
MnO4- + 8 H+ + 5e- → Mn2+ + 4 H2O E° = 1.51 V (oxidation → anode)
The amount of manganese in steel is determined by changing it to permanganate ion. The steel is first dissolved in nitric acid, producing Mn2+ ions. These ions are then oxidized to the deeply colored MnO4- ions by periodate ion (IO4-) in acid solution.
b. Calculate E° and ΔG° at 25°C for each reaction.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.