Fluorocarbons (compounds that contain both carbon ...

Question

Fluorocarbons (compounds that contain both carbon and fluorine) were, until recently, used as refrigerants. The compounds listed in the following table are all gases at 25 ^oC, and their solubilities in water at 25 ^oC and 1 atm fluorocarbon pressure are given as mass percentages.

Fluorocarbon	Solubility (mass %)
CF₄	0.0015
CClF₃	0.009
CCl₂F₂	0.028
CHClF₂	0.30

For CClF₃, calculate the molality of a saturated solution.

Jules Bruno · Accepted Answer

We’re being asked to calculate the molality of ClF3 given its solubility in mass percent.Mass or weight percent (% by mass) is the percentage of a given element or compound within a solution. The equation used to calculate for mass percent is shown below:mass percent = mass componenttotal mass×100[readmore]We will calculate the mass percent of a component in a solution using the equation:• Mass component → mass of solute• Total mass → mass of solutionmass percent =mass solutemass solution×100We will calculate the molality of CClF3 using the following steps:Step 1: Calculate the mass of the solute (CClF3).Step 2: Calculate the moles of the solute (CClF3).Step 3: Calculate the molality of CClF3.Step 1: Calculate the mass of the solute (CClF3).Given:            0.009 % CClF3Both mass solute and mass solution are in grams (g). The mass of solution is 1 g.mass percent=mass solutemass solution×100[0.009%=mass solute1 g×100]1 g[0.009%=mass solute1 g×100]1 g0.009%(100)=(mass solute)(100)(100)mass solute = 0.009%(100)mass solute = 9×105 gStep 2: Calculate the moles of the solute (CClF3).mass CClF3 (molar mass CClF3) → moles CClF3molar mass CClF3:1 C   x 12.01 g/mol = 12.01 g/mol1 Cl  x 35.45 g/mol = 35.45 g/mol3 F   x 19 g/mol = 57 g/mol _____________________________  Sum = 104.46 g/molmoles CClF3=9×105 g CClF3(1 mol CClF3104.46 g CClF3)moles CClF3 = 0.4308 molesStep 3: Calculate the molality of CClF3.moles CClF3 = 0.4308 molesmass H2O = 100 gRecall:1 kg = 103 gMolality (m)=moles solutekg solventMolality (m)=moles solutekg solvent=0.4308 moles100 g(1 kg103 g)molality CClF3 = 4.308 mol/kg or molalThe molality of 0.009% CClF3 is 4.308 mol/kg or molal.

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