Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: You may want to reference (Pages 526 - 530) Section 13.1 while completing this problem.If you compare the solubilities of the noble gases in water, you find that solubility increases from smallest ato

Problem

You may want to reference (Pages 526 - 530) Section 13.1 while completing this problem.

If you compare the solubilities of the noble gases in water, you find that solubility increases from smallest atomic weight to largest, Ar < Kr < Xe. Which of the following statements is the best explanation?
(a) The heavier the gas, the more it sinks to the bottom of the water and leaves room for more gas molecules at the
top of the water.
(b) The heavier the gas, the more dispersion forces it has, and therefore the more attractive interactions it has with water molecules.
(c) The heavier the gas, the more likely it is to hydrogen bond with water.
(d) The heavier the gas, the more likely it is to make a saturated solution in water.