Problem: The vapor pressure of benzene, C6H6, is 100.0 torr at 26.1 oC. Assuming Raoult’s law is obeyed, how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease its vapor pressure by 10.0% at 26.1 oC? The density of benzene is 0.8765 g/cm3.

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FREE Expert Solution

Step 1

Pbenzene =(100.0 torr)(10.0%100) = 10 torr


Step 2

Pbenzene =P°benzeneχbenzeneχbenzene =PbenzeneP°benzene χbenzene =10 torr100 torr

χbenzene = 0.1


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Problem Details

The vapor pressure of benzene, C6H6, is 100.0 torr at 26.1 oC. Assuming Raoult’s law is obeyed, how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease its vapor pressure by 10.0% at 26.1 oC? The density of benzene is 0.8765 g/cm3.

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