Ch.12 - SolutionsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Osmosis is the process of a solvent moving from one compartment to another, across a semipermeable membrane, toward higher solute concentration. Osmotic pressure is generated at equilibri

Problem

Initially, a U shaped tube contains pure solvent in the left arm (the solvent is H2O) and solution in the right arm (water plus solute particles). A semipermeable membrane separates the arms of the U and the fluid level in both arms is the same. There is a net movement of H2O from the pure water (left) side to the solution (right) side, across the semipermeable membrane. At equilibrium the flow of H2O is the same in both directions across the semipermeable membrane, so there is no net movement of H2O. The fluid level in the right arm of the U (the side that initially contained solution) is higher than the level in the left arm (the side that initially contained pure water). Pressure is applied to equalize fluid levels in both arms; this equals osmotic pressure.


Osmosis is the process of a solvent moving from one compartment to another, across a semipermeable membrane, toward higher solute concentration. Osmotic pressure is generated at equilibrium due to the different heights of liquid on either side of the membrane and is equivalent to the pressure needed to equalize the fluid levels across the membrane.

If the pure water in the left arm of the U-tube is replaced by a solution more concentrated than the one in the right arm, what will happen?