Problem: Osmosis is the process of a solvent moving from one compartment to another, across a semipermeable membrane, toward higher solute concentration. Osmotic pressure is generated at equilibrium due to the different heights of liquid on either side of the membrane and is equivalent to the pressure needed to equalize the fluid levels across the membrane.If the pure water in the left arm of the U-tube is replaced by a solution more concentrated than the one in the right arm, what will happen?

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We're being asked to determine what will happen when the left arm of the U-tube has a more concentrated solution that the right arm

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Initially, a U shaped tube contains pure solvent in the left arm (the solvent is H2O) and solution in the right arm (water plus solute particles). A semipermeable membrane separates the arms of the U and the fluid level in both arms is the same. There is a net movement of H2O from the pure water (left) side to the solution (right) side, across the semipermeable membrane. At equilibrium the flow of H2O is the same in both directions across the semipermeable membrane, so there is no net movement of H2O. The fluid level in the right arm of the U (the side that initially contained solution) is higher than the level in the left arm (the side that initially contained pure water). Pressure is applied to equalize fluid levels in both arms; this equals osmotic pressure.


Osmosis is the process of a solvent moving from one compartment to another, across a semipermeable membrane, toward higher solute concentration. Osmotic pressure is generated at equilibrium due to the different heights of liquid on either side of the membrane and is equivalent to the pressure needed to equalize the fluid levels across the membrane.


If the pure water in the left arm of the U-tube is replaced by a solution more concentrated than the one in the right arm, what will happen?

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