Problem: Consider two ionic solids, both composed of singly-charged ions, that have different lattice energies.Which solid will be more soluble in water, the one with the larger lattice energy or the one with the smaller lattice energy? Assume that solute-solvent interactions are the same for both solids.

FREE Expert Solution

We are asked which of the given solids given their lattice energy difference is expected to be more soluble in water. The lattice energy (or ionic bond energy) of an ionic compound depends on the equation below:

$\boxed{\mathbf{Ionic}\mathbf{ }\mathbf{Bond}\mathbf{ }\mathbf{Energy}\mathbf{=}\frac{|\mathrm{cation} \mathrm{charge}·\mathrm{anion} \mathrm{charge}|}{\mathbf{cation}\mathbf{ }\mathbf{radius}\mathbf{+}\mathbf{anion}\mathbf{ }\mathbf{radius}}}$

Radius = period number

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