We’re being asked to calculate the molality of thiophene in the solution.

When calculating for **molality**, we use the following equation:

$\overline{){\mathbf{molality}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{m}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}}$

*Solvent → C _{7}H_{8}*

**We will calculate the molality of the solution using the following steps:**

**Step 1:** Calculate the **moles of the solute**.**Step 2:** Calculate the **mass of the solvent** (in kg).**Step 3:** Calculate the **molality of the solution**.

The density of toluene (C_{7}H_{8}) is 0.867 g/mL, and the density of thiophene (C_{4}H_{4}S) is 1.065 g/mL. A solution is made by dissolving 8.60 g of thiophene in 260 mL of toluene.

Calculate the molality of thiophene in the solution.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Molality concept. You can view video lessons to learn Molality. Or if you need more Molality practice, you can also practice Molality practice problems.

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Based on our data, we think this problem is relevant for Professor Velarde's class at UB.