Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: How many grams of sulfur (S8) must be dissolved in 100.0 g naphthalene (C10H8) to make a 0.13 m solution?

Solution: How many grams of sulfur (S8) must be dissolved in 100.0 g naphthalene (C10H8) to make a 0.13 m solution?

Problem

How many grams of sulfur (S8) must be dissolved in 100.0 g naphthalene (C10H8) to make a 0.13 m solution?

Solution
  • Molality can be calculated as:

  • We will be solving for the moles of Sfirst and then mass of S8 using its molar mass

  • Molar mass of S8 is:

S - 32.07 (8) = 256.56 g/mol

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